Mikey Sends: d<sup>2</sup>y / dx<sup>2</sup> < 0

Thursday, November 03, 2005

d²y / dx² < 0

Sorry, that's a calculus condition that must be true for downward concavity.

9/28/05 at 8:13pm

1 Comments:

Michael-Fay said...: I'm behind the times because I was on Sr. retreat this weekend.

Oh, I'm gonna need the proof for the title expression. I'm not sure I understand what it's stating. :); 11/06/2005